jee-main 2023 Q84

jee-main · India · session1_29jan_shift1 Differential equations Solving Separable DEs with Initial Conditions

Let $\mathrm { y } = \mathrm { f } ( \mathrm { x } )$ be the solution of the differential equation $y ( x + 1 ) d x - x ^ { 2 } d y = 0 , y ( 1 ) = e$. Then $\lim _ { x \rightarrow 0 ^ { + } } f ( x )$ is equal to
(1) 0
(2) $\frac { 1 } { e }$
(3) $e ^ { 2 }$
(4) $\frac { 1 } { e ^ { 2 } }$

Let $\mathrm { y } = \mathrm { f } ( \mathrm { x } )$ be the solution of the differential equation $y ( x + 1 ) d x - x ^ { 2 } d y = 0 , y ( 1 ) = e$. Then $\lim _ { x \rightarrow 0 ^ { + } } f ( x )$ is equal to\\
(1) 0\\
(2) $\frac { 1 } { e }$\\
(3) $e ^ { 2 }$\\
(4) $\frac { 1 } { e ^ { 2 } }$

Paper Questions

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