If $p , q$ and $r$ are three propositions, then which of the following combination of truth values of $p , q$ and r makes the logical expression $\{ ( p \vee q ) \wedge ( ( \sim p ) \vee r ) \} \rightarrow ( ( \sim q ) \vee r )$ false ? (1) $p = \mathrm { T } , q = \mathrm { F } , r = \mathrm { T }$ (2) $p = \mathrm { T } , q = \mathrm { T } , r = \mathrm { F }$ (3) $p = \mathrm { F } , q = \mathrm { T } , r = \mathrm { F }$ (4) $p = \mathrm { T } , q = \mathrm { F } , r = \mathrm { F }$
If $p , q$ and $r$ are three propositions, then which of the following combination of truth values of $p , q$ and r makes the logical expression $\{ ( p \vee q ) \wedge ( ( \sim p ) \vee r ) \} \rightarrow ( ( \sim q ) \vee r )$ false ?\\
(1) $p = \mathrm { T } , q = \mathrm { F } , r = \mathrm { T }$\\
(2) $p = \mathrm { T } , q = \mathrm { T } , r = \mathrm { F }$\\
(3) $p = \mathrm { F } , q = \mathrm { T } , r = \mathrm { F }$\\
(4) $p = \mathrm { T } , q = \mathrm { F } , r = \mathrm { F }$