If the maximum distance of normal to the ellipse $\frac{x^2}{4} + \frac{y^2}{b^2} = 1$, $b < 2$, from the origin is 1, then the eccentricity of the ellipse is:\\
(1) $\frac{1}{\sqrt{2}}$\\
(2) $\frac{\sqrt{3}}{2}$\\
(3) $\frac{1}{2}$\\
(4) $\frac{\sqrt{3}}{4}$