For the system of linear equations $x + y + z = 6$ $\alpha x + \beta y + 7z = 3$ $x + 2y + 3z = 14$ which of the following is NOT true? (1) If $\alpha = \beta = 7$, then the system has no solution (2) If $\alpha = \beta$ and $\alpha \neq 7$ then the system has a unique solution. (3) There is a unique point $(\alpha, \beta)$ on the line $x + 2y + 18 = 0$ for which the system has infinitely many solutions (4) For every point $(\alpha, \beta) \neq (7,7)$ on the line $x - 2y + 7 = 0$, the system has infinitely many solutions.
For the system of linear equations\\
$x + y + z = 6$\\
$\alpha x + \beta y + 7z = 3$\\
$x + 2y + 3z = 14$\\
which of the following is NOT true?\\
(1) If $\alpha = \beta = 7$, then the system has no solution\\
(2) If $\alpha = \beta$ and $\alpha \neq 7$ then the system has a unique solution.\\
(3) There is a unique point $(\alpha, \beta)$ on the line $x + 2y + 18 = 0$ for which the system has infinitely many solutions\\
(4) For every point $(\alpha, \beta) \neq (7,7)$ on the line $x - 2y + 7 = 0$, the system has infinitely many solutions.