jee-main 2023 Q73

jee-main · India · session1_31jan_shift1 Chain Rule Chain Rule with Composition of Explicit Functions

Let $y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}\left(-4x^3 + 5x^2 + 1\right)^{3/2}\right)\right)$. Then, at $x = 1$,
(1) $2y' + \sqrt{3}\pi^2 y = 0$
(2) $2y' + 3\pi^2 y = 0$
(3) $\sqrt{2}y' - 3\pi^2 y = 0$
(4) $y' + 3\pi^2 y = 0$

Let $y = f(x) = \sin^3\left(\frac{\pi}{3}\cos\left(\frac{\pi}{3\sqrt{2}}\left(-4x^3 + 5x^2 + 1\right)^{3/2}\right)\right)$. Then, at $x = 1$,\\
(1) $2y' + \sqrt{3}\pi^2 y = 0$\\
(2) $2y' + 3\pi^2 y = 0$\\
(3) $\sqrt{2}y' - 3\pi^2 y = 0$\\
(4) $y' + 3\pi^2 y = 0$

Paper Questions

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