The equations of two sides AB and AC of a triangle ABC are $4 x + y = 14$ and $3 x - 2 y = 5$, respectively. The point $\left( 2 , - \frac { 4 } { 3 } \right)$ divides the third side BC internally in the ratio $2 : 1$. the equation of the side BC is\\
(1) $x + 3 y + 2 = 0$\\
(2) $x - 6 y - 10 = 0$\\
(3) $x - 3 y - 6 = 0$\\
(4) $x + 6 y + 6 = 0$