jee-main 2024 Q73

jee-main · India · session2_08apr_shift1 Standard Integrals and Reverse Chain Rule Antiderivative with Initial Condition

Let $I ( x ) = \int \frac { 6 } { \sin ^ { 2 } x ( 1 - \cot x ) ^ { 2 } } d x$. If $I ( 0 ) = 3$, then $I \left( \frac { \pi } { 12 } \right)$ is equal to
(1) $2 \sqrt { 3 }$
(2) $\sqrt { 3 }$
(3) $3 \sqrt { 3 }$
(4) $6 \sqrt { 3 }$

Let $I ( x ) = \int \frac { 6 } { \sin ^ { 2 } x ( 1 - \cot x ) ^ { 2 } } d x$. If $I ( 0 ) = 3$, then $I \left( \frac { \pi } { 12 } \right)$ is equal to\\
(1) $2 \sqrt { 3 }$\\
(2) $\sqrt { 3 }$\\
(3) $3 \sqrt { 3 }$\\
(4) $6 \sqrt { 3 }$

Paper Questions

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