ap-calculus-ab 2012 Q28

ap-calculus-ab · Usa · practice-exam Applied differentiation Kinematics via differentiation

For $t \geq 0$, the position of a particle moving along the $x$-axis is given by $x ( t ) = \sin t - \cos t$. What is the acceleration of the particle at the point where the velocity is first equal to 0 ?
(A) $- \sqrt { 2 }$
(B) $-1$
(C) 0
(D) 1
(E) $\sqrt { 2 }$

For $t \geq 0$, the position of a particle moving along the $x$-axis is given by $x ( t ) = \sin t - \cos t$. What is the acceleration of the particle at the point where the velocity is first equal to 0 ?

(A) $- \sqrt { 2 }$

(B) $-1$

(C) 0

(D) 1

(E) $\sqrt { 2 }$

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