iran-konkur 2020 Q138

iran-konkur · Other · konkur-riazi_1399_specialized_old-curriculum 3x3 Matrices Solving a 3×3 Linear System Explicitly
138- From the matrix relation $\begin{bmatrix} 2 & 3 \\ 4 & 5 \end{bmatrix} X \begin{bmatrix} 2 & -1 \\ -4 & 3 \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 8 \end{bmatrix}$, what is matrix $X$?
\[ (1)\quad \begin{bmatrix} 7 & 9 \\ 4 & 4 \end{bmatrix} \qquad (2)\quad \begin{bmatrix} 7 & 9 \\ 2 & -2 \end{bmatrix} \] \[ (3)\quad \begin{bmatrix} -9 & 7 \\ -4 & -4 \end{bmatrix} \qquad (4)\quad \begin{bmatrix} -9 & -7 \\ 4 & 4 \end{bmatrix} \]
\textbf{138-} From the matrix relation $\begin{bmatrix} 2 & 3 \\ 4 & 5 \end{bmatrix} X \begin{bmatrix} 2 & -1 \\ -4 & 3 \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 8 \end{bmatrix}$, what is matrix $X$?

\[
(1)\quad \begin{bmatrix} 7 & 9 \\ 4 & 4 \end{bmatrix} \qquad (2)\quad \begin{bmatrix} 7 & 9 \\ 2 & -2 \end{bmatrix}
\]
\[
(3)\quad \begin{bmatrix} -9 & 7 \\ -4 & -4 \end{bmatrix} \qquad (4)\quad \begin{bmatrix} -9 & -7 \\ 4 & 4 \end{bmatrix}
\]