213. To produce 2.8 tons of iron from smelting $\text{Fe}_2\text{O}_3$ ore with 50\% purity, according to the reaction: $$2\text{Fe}_2\text{O}_3(\text{s}) + 3\text{CO}(\text{g}) \rightarrow 2\text{Fe}(\text{s}) + 3\text{CO}_2(\text{g})$$ with 80\% yield, how many tons of this ore are needed, and how many kilograms of calcium oxide can absorb the $\text{CO}_2$ gas produced? (Read the options from right to left.) $(C = 12,\ O = 16,\ Ca = 40,\ Fe = 56 : \text{g.mol}^{-1})$ (1) $3250\ ,\ 10$ (2) $3250\ ,\ 8$ (3) $4250\ ,\ 10$ (4) $4250\ ,\ 8$
\textbf{213.} To produce 2.8 tons of iron from smelting $\text{Fe}_2\text{O}_3$ ore with 50\% purity, according to the reaction:
$$2\text{Fe}_2\text{O}_3(\text{s}) + 3\text{CO}(\text{g}) \rightarrow 2\text{Fe}(\text{s}) + 3\text{CO}_2(\text{g})$$
with 80\% yield, how many tons of this ore are needed, and how many kilograms of calcium oxide can absorb the $\text{CO}_2$ gas produced? (Read the options from right to left.)
$(C = 12,\ O = 16,\ Ca = 40,\ Fe = 56 : \text{g.mol}^{-1})$
(1) $3250\ ,\ 10$ \quad (2) $3250\ ,\ 8$ \quad (3) $4250\ ,\ 10$ \quad (4) $4250\ ,\ 8$