Q86. Let $\alpha \beta \gamma = 45 ; \alpha , \beta , \gamma \in \mathbb { R }$. If $x ( \alpha , 1,2 ) + y ( 1 , \beta , 2 ) + z ( 2,3 , \gamma ) = ( 0,0,0 )$ for some $x , y , z \in \mathbb { R } , x y z \neq 0$, then $6 \alpha + 4 \beta + \gamma$ is equal to $\_\_\_\_$\\