jee-main 2025 Q25

jee-main · India · session2_07apr_shift1 Not Maths
Q25. An electric field, $\overrightarrow { \mathrm { E } } = \frac { 2 \hat { i } + 6 \hat { j } + 8 \hat { k } } { \sqrt { 6 } }$ passes through the surface of $4 \mathrm {~m} ^ { 2 }$ area having unit vector $\hat { n } = \left( \frac { 2 \hat { i } + \hat { j } + \hat { k } } { \sqrt { 6 } } \right)$. The electric flux for that surface is $\_\_\_\_$ Vm.
Q25. An electric field, $\overrightarrow { \mathrm { E } } = \frac { 2 \hat { i } + 6 \hat { j } + 8 \hat { k } } { \sqrt { 6 } }$ passes through the surface of $4 \mathrm {~m} ^ { 2 }$ area having unit vector $\hat { n } = \left( \frac { 2 \hat { i } + \hat { j } + \hat { k } } { \sqrt { 6 } } \right)$. The electric flux for that surface is $\_\_\_\_$ Vm.