A rectangle is formed by lines $x = 0 , y = 0 , x = 3 , y = 4$. A line perpendicular to $3 x + 4 y + 6 = 0$ divides the rectangle into two equal parts, then the distance of the line from ( $- 1 , \frac { 3 } { 2 }$ ) is\
(A) 2\
(B) $\frac { 8 } { 5 }$\
(C) $\frac { 6 } { 5 }$\
(D) $\frac { 17 } { 10 }$