Among the following compounds\
$\mathrm { HNO } _ { 3 } , \mathrm { H } _ { 2 } \mathrm { SO } _ { 4 } , \mathrm { O } _ { 3 } , \mathrm { NF } _ { 3 }$\
Bond angle for the compound which has highest number of lone pairs.\
(A) $116 ^ { \circ }$\
(B) $107 ^ { \circ }$\
(C) $120 ^ { \circ }$\
(D) $102 ^ { \circ }$