gaokao 2022 Q19

gaokao · China · national-B-arts 12 marks Linear regression
After years of environmental remediation, a certain region has transformed barren mountains into green mountains and clear waters. To estimate the total timber volume of a certain tree species in a forest area, 10 trees of this species were randomly selected. The cross-sectional area at the base (in $\mathrm { m } ^ { 2 }$ ) and timber volume (in $\mathrm { m } ^ { 3 }$ ) of each tree were measured, yielding the following data:
Sample number $i$12345678910Total
Base cross-sectional area $x _ { i }$0.040.060.040.080.080.050.050.070.070.060.6
Timber volume $y _ { i }$0.250.400.220.540.510.340.360.460.420.403.9

It is calculated that $\sum _ { i = 1 } ^ { 10 } x _ { i } ^ { 2 } = 0.038 , ~ \sum _ { i = 1 } ^ { 10 } y _ { i } ^ { 2 } = 1.6158 , \sum _ { i = 1 } ^ { 10 } x _ { i } y _ { i } = 0.2474$ .
(1) Estimate the average base cross-sectional area and average timber volume per tree of this species in the forest area;
(2) Find the sample correlation coefficient between the base cross-sectional area and timber volume of this tree species (accurate to 0.01);
(3) The base cross-sectional area of all trees of this species in the forest area was measured, and the total base cross-sectional area of all such trees is $186 \mathrm {~m} ^ { 2 }$ . Given that the timber volume of a tree is approximately proportional to its base cross-sectional area, use the above data to estimate the total timber volume of this tree species in the forest area.
Note: Correlation coefficient $r = \frac { \sum _ { i = 1 } ^ { n } \left( x _ { i } - \bar { x } \right) \left( y _ { i } - \bar { y } \right) } { \sqrt { \sum _ { i = 1 } ^ { n } \left( x _ { i } - \bar { x } \right) ^ { 2 } \sum _ { i = 1 } ^ { n } \left( y _ { i } - \bar { y } \right) ^ { 2 } } } , \sqrt { 1.896 } \approx 1.377$ .
After years of environmental remediation, a certain region has transformed barren mountains into green mountains and clear waters. To estimate the total timber volume of a certain tree species in a forest area, 10 trees of this species were randomly selected. The cross-sectional area at the base (in $\mathrm { m } ^ { 2 }$ ) and timber volume (in $\mathrm { m } ^ { 3 }$ ) of each tree were measured, yielding the following data:

\begin{center}
\begin{tabular}{ | c | c c c c c c c c c c | c | }
\hline
Sample number $i$ & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & Total \\
\hline
Base cross-sectional area $x _ { i }$ & 0.04 & 0.06 & 0.04 & 0.08 & 0.08 & 0.05 & 0.05 & 0.07 & 0.07 & 0.06 & 0.6 \\
Timber volume $y _ { i }$ & 0.25 & 0.40 & 0.22 & 0.54 & 0.51 & 0.34 & 0.36 & 0.46 & 0.42 & 0.40 & 3.9 \\
\hline
\end{tabular}
\end{center}

It is calculated that $\sum _ { i = 1 } ^ { 10 } x _ { i } ^ { 2 } = 0.038 , ~ \sum _ { i = 1 } ^ { 10 } y _ { i } ^ { 2 } = 1.6158 , \sum _ { i = 1 } ^ { 10 } x _ { i } y _ { i } = 0.2474$ .

(1) Estimate the average base cross-sectional area and average timber volume per tree of this species in the forest area;

(2) Find the sample correlation coefficient between the base cross-sectional area and timber volume of this tree species (accurate to 0.01);

(3) The base cross-sectional area of all trees of this species in the forest area was measured, and the total base cross-sectional area of all such trees is $186 \mathrm {~m} ^ { 2 }$ . Given that the timber volume of a tree is approximately proportional to its base cross-sectional area, use the above data to estimate the total timber volume of this tree species in the forest area.

Note: Correlation coefficient $r = \frac { \sum _ { i = 1 } ^ { n } \left( x _ { i } - \bar { x } \right) \left( y _ { i } - \bar { y } \right) } { \sqrt { \sum _ { i = 1 } ^ { n } \left( x _ { i } - \bar { x } \right) ^ { 2 } \sum _ { i = 1 } ^ { n } \left( y _ { i } - \bar { y } \right) ^ { 2 } } } , \sqrt { 1.896 } \approx 1.377$ .