In this part, $d$ equals 1 and we simply denote $0_d = 0$. Moreover, $p$ is an element of $]0,1[$, $q = 1 - p$ and the distribution of $X$ is given by
$$P ( X = 1 ) = p \quad \text{and} \quad P ( X = - 1 ) = q .$$
For $n \in \mathbb{N}$, determine $P \left( S _ { 2 n + 1 } = 0 \right)$ and justify the equality:
$$P \left( S _ { 2 n } = 0 \right) = \binom { 2 n } { n } ( p q ) ^ { n }$$