A group of 64 players in a chess tournament needs to be divided into 32 groups of 2 players each. In how many ways can this be done?\\
(A) $\frac { 64 ! } { 32 ! 2 ^ { 32 } }$\\
(B) $\binom { 64 } { 2 } \binom { 62 } { 2 } \cdots \binom { 4 } { 2 } \binom { 2 } { 2 }$\\
(C) $\frac { 64 ! } { 32 ! 32 ! }$\\
(D) $\frac { 64 ! } { 2 ^ { 64 } }$