jee-advanced 2010 Q46

jee-advanced · India · paper1 Circles Circle Equation Derivation

The circle $x ^ { 2 } + y ^ { 2 } - 8 x = 0$ and hyperbola $\frac { x ^ { 2 } } { 9 } - \frac { y ^ { 2 } } { 4 } = 1$ intersect at the points $A$ and $B$.
Equation of the circle with AB as its diameter is
A) $x ^ { 2 } + y ^ { 2 } - 12 x + 24 = 0$
B) $x ^ { 2 } + y ^ { 2 } + 12 x + 24 = 0$
C) $x ^ { 2 } + y ^ { 2 } + 24 x - 12 = 0$
D) $x ^ { 2 } + y ^ { 2 } - 24 x - 12 = 0$

The circle $x ^ { 2 } + y ^ { 2 } - 8 x = 0$ and hyperbola $\frac { x ^ { 2 } } { 9 } - \frac { y ^ { 2 } } { 4 } = 1$ intersect at the points $A$ and $B$.

Equation of the circle with AB as its diameter is\\
A) $x ^ { 2 } + y ^ { 2 } - 12 x + 24 = 0$\\
B) $x ^ { 2 } + y ^ { 2 } + 12 x + 24 = 0$\\
C) $x ^ { 2 } + y ^ { 2 } + 24 x - 12 = 0$\\
D) $x ^ { 2 } + y ^ { 2 } - 24 x - 12 = 0$

Paper Questions

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