jee-main 2011 Q14

jee-main · India Not Maths

Two particles are executing simple harmonic motion of the same amplitude A and frequency $\omega$ along the $x$ axis. Their mean position is separated by distance $X_{0}\left(X_{0}>A\right)$. If the maximum separation between them is $\left(X_{0}+A\right)$, the phase difference between their motion is:
(1) $\frac{\pi}{3}$
(2) $\frac{\pi}{4}$
(3) $\frac{\pi}{6}$
(4) $\frac{\pi}{2}$

Two particles are executing simple harmonic motion of the same amplitude A and frequency $\omega$ along the $x$ axis. Their mean position is separated by distance $X_{0}\left(X_{0}>A\right)$. If the maximum separation between them is $\left(X_{0}+A\right)$, the phase difference between their motion is:\\
(1) $\frac{\pi}{3}$\\
(2) $\frac{\pi}{4}$\\
(3) $\frac{\pi}{6}$\\
(4) $\frac{\pi}{2}$

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