The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in $\text{mol kg}^{-1}$) of the aqueous solution is: (1) $13.88 \times 10^{-3}$ (2) $13.88 \times 10^{-1}$ (3) $13.88$ (4) $13.88 \times 10^{-2}$
The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in $\text{mol kg}^{-1}$) of the aqueous solution is:\\
(1) $13.88 \times 10^{-3}$\\
(2) $13.88 \times 10^{-1}$\\
(3) $13.88$\\
(4) $13.88 \times 10^{-2}$