If the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ meets the line $\frac{x}{7} + \frac{y}{2\sqrt{6}} = 1$ on the $x$-axis and the line $\frac{x}{7} - \frac{y}{2\sqrt{6}} = 1$ on the $y$-axis, then the eccentricity of the ellipse is\\
(1) $\frac{5}{7}$\\
(2) $\frac{2\sqrt{6}}{7}$\\
(3) $\frac{3}{7}$\\
(4) $\frac{2\sqrt{5}}{7}$