Let the foci of the ellipse $\frac{x^2}{16} + \frac{y^2}{7} = 1$ and the hyperbola $\frac{x^2}{144} - \frac{y^2}{\alpha} = \frac{1}{25}$ coincide. Then the length of the latus rectum of the hyperbola is:\\
(1) $\frac{32}{9}$\\
(2) $\frac{18}{5}$\\
(3) $\frac{27}{4}$\\
(4) $\frac{27}{10}$