jee-main 2022 Q2

jee-main · India · session2_25jul_shift2 Projectiles Finding Angle of Projection from Given Conditions
A ball is projected from the ground with a speed $15 \mathrm{~m}\mathrm{~s}^{-1}$ at an angle $\theta$ with horizontal so that its range and maximum height are equal, then $\tan\theta$ will be equal to
(1) $\frac{1}{4}$
(2) $\frac{1}{2}$
(3) 2
(4) 4 
A ball is projected from the ground with a speed $15 \mathrm{~m}\mathrm{~s}^{-1}$ at an angle $\theta$ with horizontal so that its range and maximum height are equal, then $\tan\theta$ will be equal to\\
(1) $\frac{1}{4}$\\
(2) $\frac{1}{2}$\\
(3) 2\\
(4) 4
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