jee-main 2023 Q61

jee-main · India · session1_31jan_shift2 Exponential Functions Exponential Equation Solving
The equation $e^{4x} + 8e^{3x} + 13e^{2x} - 8e^x + 1 = 0, x \in R$ has:
(1) four solutions two of which are negative
(2) two solutions and both are negative
(3) no solution
(4) two solutions and only one of them is negative
The equation $e^{4x} + 8e^{3x} + 13e^{2x} - 8e^x + 1 = 0, x \in R$ has:\\
(1) four solutions two of which are negative\\
(2) two solutions and both are negative\\
(3) no solution\\
(4) two solutions and only one of them is negative