Let $a_1, a_2, a_3, \ldots$ be an A.P. If $a_7 = 3$, the product $(a_1 a_4)$ is minimum and the sum of its first $n$ terms is zero then $n! - 4a_{n(n+2)}$ is equal to (1) $\frac{381}{4}$ (2) 9 (3) $\frac{33}{4}$ (4) 24
Let $a_1, a_2, a_3, \ldots$ be an A.P. If $a_7 = 3$, the product $(a_1 a_4)$ is minimum and the sum of its first $n$ terms is zero then $n! - 4a_{n(n+2)}$ is equal to\\
(1) $\frac{381}{4}$\\
(2) 9\\
(3) $\frac{33}{4}$\\
(4) 24