jee-main 2024 Q79

jee-main · India · session2_06apr_shift1 Vectors: Lines & Planes Distance Computation (Point-to-Plane or Line-to-Line)

The shortest distance between the lines $\frac { x - 3 } { 2 } = \frac { y + 15 } { - 7 } = \frac { z - 9 } { 5 }$ and $\frac { x + 1 } { 2 } = \frac { y - 1 } { 1 } = \frac { z - 9 } { - 3 }$ is
(1) $8 \sqrt { 3 }$
(2) $4 \sqrt { 3 }$
(3) $5 \sqrt { 3 }$
(4) $6 \sqrt { 3 }$

The shortest distance between the lines $\frac { x - 3 } { 2 } = \frac { y + 15 } { - 7 } = \frac { z - 9 } { 5 }$ and $\frac { x + 1 } { 2 } = \frac { y - 1 } { 1 } = \frac { z - 9 } { - 3 }$ is\\
(1) $8 \sqrt { 3 }$\\
(2) $4 \sqrt { 3 }$\\
(3) $5 \sqrt { 3 }$\\
(4) $6 \sqrt { 3 }$

Paper Questions

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