jee-main 2025 Q17

jee-main · India · session1_24jan_shift1 Differential equations Solving Separable DEs with Initial Conditions

Let $y = y(x)$ be the solution of the differential equation $\left(xy - 5x^2\sqrt{1+x^2}\right)dx + \left(1+x^2\right)dy = 0$, $y(0) = 0$. Then $y(\sqrt{3})$ is equal to
(1) $\sqrt{\frac{15}{2}}$
(2) $\frac{5\sqrt{3}}{2}$
(3) $2\sqrt{2}$
(4) $\sqrt{\frac{14}{3}}$

Let $y = y(x)$ be the solution of the differential equation $\left(xy - 5x^2\sqrt{1+x^2}\right)dx + \left(1+x^2\right)dy = 0$, $y(0) = 0$. Then $y(\sqrt{3})$ is equal to\\
(1) $\sqrt{\frac{15}{2}}$\\
(2) $\frac{5\sqrt{3}}{2}$\\
(3) $2\sqrt{2}$\\
(4) $\sqrt{\frac{14}{3}}$

Paper Questions

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