csat-suneung 2005 Q16

csat-suneung · South-Korea · csat__math-humanities 3 marks Approximating Binomial to Normal Distribution
The following table shows the results of a survey on customer preferences for hiking boots by manufacturer at a certain department store.
ManufacturerABCDTotal
Preference (\%)20282527100

When 192 customers each purchase one pair of hiking boots, what is the probability that 42 or more customers will choose product C, using the standard normal distribution table on the right? [3 points]
$z$$\mathrm { P } ( 0 \leqq Z \leqq z )$
0.50.1915
1.00.3413
1.50.4332
2.00.4772

(1) 0.6915
(2) 0.7745
(3) 0.8256
(4) 0.8332
(5) 0.8413
The following table shows the results of a survey on customer preferences for hiking boots by manufacturer at a certain department store.

\begin{center}
\begin{tabular}{ | c | c | c | c | c | c | }
\hline
Manufacturer & A & B & C & D & Total \\
\hline
Preference (\%) & 20 & 28 & 25 & 27 & 100 \\
\hline
\end{tabular}
\end{center}

When 192 customers each purchase one pair of hiking boots, what is the probability that 42 or more customers will choose product C, using the standard normal distribution table on the right? [3 points]

\begin{center}
\begin{tabular}{ | c | c | }
\hline
$z$ & $\mathrm { P } ( 0 \leqq Z \leqq z )$ \\
\hline
0.5 & 0.1915 \\
\hline
1.0 & 0.3413 \\
\hline
1.5 & 0.4332 \\
\hline
2.0 & 0.4772 \\
\hline
\end{tabular}
\end{center}

(1) 0.6915\\
(2) 0.7745\\
(3) 0.8256\\
(4) 0.8332\\
(5) 0.8413