grandes-ecoles 2024 Q1.10
Convergence proof and limit determination
Let $\left( u _ { n } \right) _ { n \in \mathbb { N } } \in \mathbb { C } ^ { \mathbb { N } }$ and $\ell \in \mathbb { C }$. The purpose of this question is to prove that $$\left( \lim _ { n \rightarrow + \infty } \sigma _ { n } = \ell \text { and } e _ { n } = O \left( \frac { 1 } { n } \right) \right) \Rightarrow \left( \lim _ { n \rightarrow + \infty } u _ { n } = \ell \right) \qquad \text{(Strong Hardy)}$$
We suppose that $\lim _ { n \rightarrow + \infty } \sigma _ { n } = \ell$ and $e _ { n } = O \left( \frac { 1 } { n } \right)$.
(a) Let $0 \leqslant n < m$. Prove that $$\sum _ { k = n + 1 } ^ { m } u _ { k } - ( m - n ) u _ { n } = \sum _ { j = n } ^ { m - 1 } ( m - j ) e _ { j }$$
(b) Deduce that there exists a constant $C > 0$ such that for all $2 \leqslant n < m$, we have $$\left| \frac { ( m + 1 ) \sigma _ { m } - ( n + 1 ) \sigma _ { n } } { m - n } - u _ { n } \right| \leqslant C \ln \left( \frac { m - 1 } { n - 1 } \right)$$ and $$\left| u _ { n } - \ell \right| \leqslant C \ln \left( \frac { m - 1 } { n - 1 } \right) + \frac { m + 1 } { m - n } \left( \left| \sigma _ { m } - \ell \right| + \left| \sigma _ { n } - \ell \right| \right) .$$
(c) Deduce (Strong Hardy). Hint: one may take $m = 1 + \lfloor \alpha n \rfloor$ with a parameter $\alpha > 1$ to be chosen, where $\lfloor x \rfloor$ denotes the integer part of $x \in \mathbb { R }$.