The purpose of this exercise is to study sequences of positive terms whose first term $u_0$ is strictly greater than 1 and possessing the following property: for every natural number $n > 0$, the sum of the first $n$ consecutive terms equals the product of the first $n$ consecutive terms. We admit that such a sequence exists and we denote it $(u_n)$. It therefore satisfies three properties:
$u_0 > 1$,
for all $n \geqslant 0, u_n \geqslant 0$,
for all $n > 0, u_0 + u_1 + \cdots + u_{n-1} = u_0 \times u_1 \times \cdots \times u_{n-1}$.
We choose $u_0 = 3$. Determine $u_1$ and $u_2$.
For every integer $n > 0$, we denote $s_n = u_0 + u_1 + \cdots + u_{n-1} = u_0 \times u_1 \times \cdots \times u_{n-1}$. In particular, $s_1 = u_0$. a. Verify that for every integer $n > 0, s_{n+1} = s_n + u_n$ and $s_n > 1$. b. Deduce that for every integer $n > 0$, $$u_n = \frac{s_n}{s_n - 1}$$ c. Show that for all $n \geqslant 0, u_n > 1$.
Using the algorithm opposite, we want to calculate the term $u_n$ for a given value of $n$. a. Copy and complete the processing part of the algorithm:
Input:
Enter $n$
Enter $u$
Processing:
$s$ takes the value $u$
For $i$ going from 1 to $n$:
$u$ takes the value $\ldots$
$s$ takes the value $\ldots$
End For
Output:
Display $u$
b. The table below gives values rounded to the nearest thousandth of $u_n$ for different values of the integer $n$:
$n$
0
5
10
20
30
40
$u_n$
3
1.140
1.079
1.043
1.030
1.023
What conjecture can be made about the convergence of the sequence $(u_n)$?
a. Justify that for every integer $n > 0, s_n > n$. b. Deduce the limit of the sequence $(s_n)$ then that of the sequence $(u_n)$.
For a natural number $k$, $$a _ { k } = \lim _ { n \rightarrow \infty } \frac { \left( \frac { 6 } { k } \right) ^ { n + 1 } } { \left( \frac { 6 } { k } \right) ^ { n } + 1 }$$ Find the value of $\sum _ { k = 1 } ^ { 10 } k a _ { k }$. [4 points]
As shown in the figure, for a square ABCD with side length 5, let the five division points of diagonal BD be $\mathrm { P } _ { 1 } , \mathrm { P } _ { 2 } , \mathrm { P } _ { 3 } , \mathrm { P } _ { 4 }$ in order from point B. Draw squares with diagonals $\mathrm { BP } _ { 1 } , \mathrm { P } _ { 2 } \mathrm { P } _ { 3 } , \mathrm { P } _ { 4 } \mathrm { D }$ and circles with diameters $\mathrm { P } _ { 1 } \mathrm { P } _ { 2 } , \mathrm { P } _ { 3 } \mathrm { P } _ { 4 }$, then color the figure-eight-shaped region to obtain figure $R _ { 1 }$. In figure $R _ { 1 }$, let $\mathrm { Q } _ { 1 }$ be the vertex of the square with diagonal $\mathrm { P } _ { 2 } \mathrm { P } _ { 3 }$ closest to point A, and $\mathrm { Q } _ { 2 }$ be the vertex closest to point C. Draw squares with diagonals $\mathrm { AQ } _ { 1 }$ and $\mathrm { CQ } _ { 2 }$, and in these 2 new squares, draw figure-eight-shaped figures using the same method as for $R _ { 1 }$ and color them to obtain figure $R _ { 2 }$. In figure $R _ { 2 }$, in the squares with diagonals $\mathrm { AQ } _ { 1 }$ and $\mathrm { CQ } _ { 2 }$, draw figure-eight-shaped figures using the same method as obtaining $R _ { 2 }$ from $R _ { 1 }$ and color them to obtain figure $R _ { 3 }$. Continuing this process, let $S _ { n }$ be the area of the colored region in the $n$-th figure $R _ { n }$. What is the value of $\lim _ { n \rightarrow \infty } S _ { n }$? [3 points] (1) $\frac { 24 } { 17 } ( \pi + 3 )$ (2) $\frac { 25 } { 17 } ( \pi + 3 )$ (3) $\frac { 26 } { 17 } ( \pi + 3 )$ (4) $\frac { 24 } { 17 } ( 2 \pi + 1 )$ (5) $\frac { 25 } { 17 } ( 2 \pi + 1 )$
As shown in the figure, there is a circle $O$ with diameter AB of length 4. Let C be the center of the circle, and let D and P be the midpoints of segments AC and BC, respectively. Let E and Q be the points where the perpendicular bisector of segment AC and the perpendicular bisector of segment BC meet the upper semicircle of circle $O$, respectively. Draw a square DEFG with side DE that meets circle $O$ at point A and has diagonal DF, and draw a square PQRS with side PQ that meets circle $O$ at point B and has diagonal PR. Color the $\square$-shaped figure that is the common part of the interior of circle $O$ and the interior of square DEFG, and the $\square$-shaped figure that is the common part of the interior of circle $O$ and the interior of square PQRS to obtain figure $R _ { 1 }$. In figure $R _ { 1 }$, draw circle $O _ { 1 }$ centered at point F with radius $\frac { 1 } { 2 } \overline { \mathrm { DE } }$, and circle $O _ { 2 }$ centered at point R with radius $\frac { 1 } { 2 } \overline { \mathrm { PQ } }$. Color 2 $\square$-shaped figures and 2 $\square$-shaped figures created in the same way as obtaining figure $R _ { 1 }$ on the two circles $O _ { 1 }$ and $O _ { 2 }$ to obtain figure $R _ { 2 }$. Continuing this process, let $S _ { n }$ be the area of the colored part in figure $R _ { n }$ obtained the $n$-th time. What is the value of $\lim _ { n \rightarrow \infty } S _ { n }$? [4 points] (1) $\frac { 12 \pi - 9 \sqrt { 3 } } { 10 }$ (2) $\frac { 8 \pi - 6 \sqrt { 3 } } { 5 }$ (3) $\frac { 32 \pi - 24 \sqrt { 3 } } { 15 }$ (4) $\frac { 28 \pi - 21 \sqrt { 3 } } { 10 }$ (5) $\frac { 16 \pi - 12 \sqrt { 3 } } { 5 }$
The sequence $\left\{ a _ { n } \right\}$ satisfies the following conditions for all natural numbers $n$. (가) $a _ { 2 n } = a _ { n } - 1$ (나) $a _ { 2 n + 1 } = 2 a _ { n } + 1$ When $a _ { 20 } = 1$, what is the value of $\sum _ { n = 1 } ^ { 63 } a _ { n }$? [4 points] (1) 704 (2) 712 (3) 720 (4) 728 (5) 736
For a sequence $\left\{ a _ { n } \right\}$ with first term 1, satisfying for all natural numbers $n$: $$a _ { n + 1 } = \begin{cases} 2 a _ { n } & \left( a _ { n } < 7 \right) \\ a _ { n } - 7 & \left( a _ { n } \geq 7 \right) \end{cases}$$ what is the value of $\sum _ { k = 1 } ^ { 8 } a _ { k }$? [3 points] (1) 30 (2) 32 (3) 34 (4) 36 (5) 38
Let $f$ be the function defined by $$f(x) = \sum_{n=1}^{+\infty} \left(\frac{1}{n+x} - \frac{1}{n}\right)$$ Let $k \in \mathbb{N}^{*}$. For all $x \in \mathcal{D}_{f}$, verify that $x + k \in \mathcal{D}_{f}$, then calculate $f(x+k) - f(x)$.
110. The sequence $a_n = \begin{cases} 2^k & ; \ n = 2k \\ -2k+4 & ; \ n = 2k+1 \\ \left[\dfrac{n}{k+2}\right]+a & ; \ n = 2k+2 \end{cases}$ is defined for integer values of $n$, and is assumed. If the sum of the first 10 terms of this sequence is 19, then the value of $a_2 + a_5 + a_4 + \cdots + a_{29}$ is: (1) $-2$ (2) zero (3) $2$ (4) $1$
For any real number $x$, let $\tan^{-1}(x)$ denote the unique real number $\theta$ in $(-\pi/2, \pi/2)$ such that $\tan\theta = x$. Then $\lim_{n \to \infty} \sum_{m=1}^{n} \tan^{-1}\left\{\frac{1}{1+m+m^{2}}\right\}$ (a) Is equal to $\pi/2$ (b) Is equal to $\pi/4$ (c) Does not exist (d) None of the above.
Consider an arithmetic series and a geometric series having four initial terms from the set $\{ 11,8,21,16,26,32,4 \}$. If the last terms of these series are the maximum possible four digit numbers, then the number of common terms in these two series is equal to $\_\_\_\_$.
Let $\left\{ a _ { n } \right\} _ { n = 1 } ^ { \infty }$ be a sequence such that $a _ { 1 } = 1 , a _ { 2 } = 1$ and $a _ { n + 2 } = 2 a _ { n + 1 } + a _ { n }$ for all $n \geq 1$. Then the value of $47 \sum _ { n = 1 } ^ { \infty } \left( \frac { a _ { n } } { 2 ^ { 3 n } } \right)$ is equal to $\underline{\hspace{1cm}}$.
Let $a _ { 1 } = b _ { 1 } = 1$ and $a _ { n } = a _ { n - 1 } + ( n - 1 ) , b _ { n } = b _ { n - 1 } + \mathrm { a } _ { n - 1 } , \forall n \geq 2$. If $\mathrm { S } = \sum _ { \mathrm { n } = 1 } ^ { 10 } \left( \frac { b _ { n } } { 2 ^ { n } } \right)$ and $\mathrm { T } = \sum _ { n = 1 } ^ { 8 } \frac { \mathrm { n } } { 2 ^ { n - 1 } }$ then $2 ^ { 7 } ( 2 S - T )$ is equal to $\_\_\_\_$
Let $\left\langle a _ { n } \right\rangle$ be a sequence such that $a _ { 1 } + a _ { 2 } + \ldots + a _ { n } = \frac { n ^ { 2 } + 3 n } { ( n + 1 ) ( n + 2 ) }$. If $28 \sum _ { k = 1 } ^ { 10 } \frac { 1 } { a _ { k } } = p _ { 1 } p _ { 2 } p _ { 3 } \ldots p _ { m }$, where $p _ { 1 } , p _ { 2 } , \ldots p _ { m }$ are the first $m$ prime numbers, then $m$ is equal to (1) 5 (2) 8 (3) 6 (4) 7
Q82. Let the first term of a series be $T _ { 1 } = 6$ and its $r ^ { \text {th } }$ term $T _ { r } = 3 T _ { r - 1 } + 6 ^ { r } , r = 2,3 , \quad n$. If the sum of the first $n$ terms of this series is $\frac { 1 } { 5 } \left( n ^ { 2 } - 12 n + 39 \right) \left( 4 \cdot 6 ^ { n } - 5 \cdot 3 ^ { n } + 1 \right)$, then $n$ is equal to $\_\_\_\_$