Finding roots or coefficients of a quadratic using Vieta's relations
The question asks to find roots, coefficients, or a related quadratic equation by applying relationships between roots and coefficients (sum and product of roots) rather than directly solving the equation.
Let $\alpha _ { \theta }$ and $\beta _ { \theta }$ be the distinct roots of $2 x ^ { 2 } + ( \cos \theta ) x - 1 = 0 , \theta \in ( 0,2 \pi )$. If m and M are the minimum and the maximum values of $\alpha _ { \theta } ^ { 4 } + \beta _ { \theta } ^ { 4 }$, then $16 ( M + m )$ equals : (1) 24 (2) 25 (3) 17 (4) 27
Let $a, b, c$ be nonzero real numbers, and the two roots of the quadratic equation $ax^2 + bx + c = 0$ both lie between 1 and 3. Select the equation whose two roots must lie between 4 and 5. (1) $a(x-2)^2 + b(x-2) + c = 0$ (2) $a(x+2)^2 + b(x+2) + c = 0$ (3) $a(2x-7)^2 + b(2x-7) + c = 0$ (4) $a\left(\frac{x+7}{2}\right)^2 + b\left(\frac{x+7}{2}\right) + c = 0$ (5) $a(3x-11)^2 + b(3x-11) + c = 0$
The quadratic expression $x^2 - 14x + 9$ factorises as $(x - \alpha)(x - \beta)$, where $\alpha$ and $\beta$ are positive real numbers. Which quadratic expression can be factorised as $(x - \sqrt{\alpha})(x - \sqrt{\beta})$? A $x^2 - \sqrt{10}x + 3$ B $x^2 - \sqrt{14}x + 3$ C $x^2 - \sqrt{20}x + 3$ D $x^2 - 178x + 81$ E $x^2 - 176x + 81$ F $x^2 + 196x + 81$
$$(3x-1)(x+1)+(3x-1)(x-2)=0$$ What is the sum of the real numbers $x$ that satisfy the equation? A) $\frac{2}{3}$ B) $\frac{3}{4}$ C) $\frac{3}{5}$ D) $\frac{5}{6}$ E) $\frac{7}{6}$
Let $a$ and $b$ be positive real numbers. For each of the equations $$\begin{aligned}
& ax^{2} - 2x + b = 0 \\
& bx^{2} - 3bx + a = 0
\end{aligned}$$ the sum of roots is 1 more than the product of roots. Which of the following could be the quadratic equation whose roots are $a$ and $b$? A) $9x^{2} + 8x + 18 = 0$ B) $9x^{2} - 14x + 8 = 0$ C) $9x^{2} - 18x + 14 = 0$ D) $9x^{2} - 8x + 14 = 0$ E) $9x^{2} - 18x + 8 = 0$