$$(3x-1)(x+1)+(3x-1)(x-2)=0$$ What is the sum of the real numbers $x$ that satisfy the equation? A) $\frac{2}{3}$ B) $\frac{3}{4}$ C) $\frac{3}{5}$ D) $\frac{5}{6}$ E) $\frac{7}{6}$
$$(3x-1)(x+1)+(3x-1)(x-2)=0$$
What is the sum of the real numbers $x$ that satisfy the equation?
A) $\frac{2}{3}$\\
B) $\frac{3}{4}$\\
C) $\frac{3}{5}$\\
D) $\frac{5}{6}$\\
E) $\frac{7}{6}$