$$(2x-1)\left(4x^{2}-1\right)<0$$
Which of the following open intervals is the solution set of the inequality in real numbers?
A) $\left(-\infty, \frac{-1}{2}\right)$
B) $\left(\frac{-1}{2}, 0\right)$
C) $\left(\frac{-1}{2}, \frac{1}{2}\right)$
D) $\left(\frac{1}{4}, \frac{1}{2}\right)$
E) $\left(\frac{1}{2}, \infty\right)$
$$(2x-1)\left(4x^{2}-1\right)<0$$

Which of the following open intervals is the solution set of the inequality in real numbers?

A) $\left(-\infty, \frac{-1}{2}\right)$\\
B) $\left(\frac{-1}{2}, 0\right)$\\
C) $\left(\frac{-1}{2}, \frac{1}{2}\right)$\\
D) $\left(\frac{1}{4}, \frac{1}{2}\right)$\\
E) $\left(\frac{1}{2}, \infty\right)$