16. The minimum value of $\left| a + b w + c w ^ { 2 } \right|$, where $a , b$ and $c$ are all not equal integers and $w \left( \begin{array} { l l } 1 & 1 \end{array} \right)$ is a cube root of unity, is:
(a) $\sqrt { } 3$
(b) $1 / 3$
(c) 1
(d) 0
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- If $P = \left[ \begin{array} { c c } \sqrt { 3 } / 2 & 1 / 2 \\ - 1 / 2 & \sqrt { 3 } / 2 \end{array} \right] , A = \left[ \begin{array} { l l } 1 & 1 \\ 0 & 1 \end{array} \right]$ and $\mathrm { Q } = \mathrm { PAP } ^ { \top }$, then $\mathrm { P } ^ { \top } \mathrm { Q } ^ { 2005 } \mathrm { P }$ is:
(a) $\left[ \begin{array} { c c } 1 & 2005 \\ 0 & 1 \end{array} \right]$
(b) $\left[ \begin{array} { c c } 1 & 2005 \\ 2005 & 1 \end{array} \right]$
(c) $\left[ \begin{array} { c c } 1 & 0 \\ 2005 & 1 \end{array} \right] ^ { 1 }$
(d) $\left[ \begin{array} { l l } 1 & 0 \\ 0 & 1 \end{array} \right]$ - The shaded region, where $P \equiv ( - 1,0 ) , Q \equiv ( - 1 + \sqrt { } 2 , \sqrt { } 2 )$ $R \equiv ( - 1 + \sqrt { } 2 , - \sqrt { } 2 ) , S \equiv ( 1,0 )$ is represented by:
(a) $| z + 1 | > 2 , | \arg ( z + 1 ) | < n / 4$
(b) $| z + 1 | < 2 , | \arg ( z + 1 ) | < n / 2$
(c) $| z - 1 | > 2 , | \arg ( z + 1 ) | > \pi / 4$
(d) $| z - 1 | < 2 , | \arg ( z + 1 ) | > n / 2$ - The number of ordered pairs ( $a , \beta$ ), where $a , \beta \hat { I } ( - \Pi , \Pi )$ satisfying $\cos ( a - \beta ) = 1$ and $\cos ( a + \beta ) = 1 / e$ is :
(a) 0
(b) 1
(c) 2
(d) 4 - Let $f ( x ) = | x | - 1$, then points where $f ( x )$ is not differentiable is/(are):
(a) $0 , + 1$
(b) + 1
(c) 0
(d) 1 - The second degree polynomial $f ( x )$, satisfying $f ( 0 ) = 0 , f ( 1 ) = 1 , f ^ { \prime } ( x ) > 0$ for all $x \hat { I }$ ( 0 , 1) :
(a) $f ( x ) = f$
(b) $f ( x ) = a x + ( 1 - a ) x ^ { 2 } ; \forall a \hat { I } ( 0 , ¥ )$
(c) $f ( x ) = a x + ( 1 - a ) x ^ { 2 } ; \forall a \hat { I } ( 0,2 )$
(d) no such polynomial - If $f$ is a differentiable function satisfying $f ( 1 / n ) = 0$ for all $n > 1 , n \hat { I } I$, then :
(a) $f ( x ) = 0 , x \hat { I } ( 0,1 ]$
(b) $f ^ { \prime } ( 0 ) = 0 = f ( 0 )$
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(c) $f ( 0 ) = 0$ but $f ^ { \prime } ( 0 )$ not necessarily zero
(d) $| f ( x ) | < 1 , x \hat { I } ( 0,1 ]$