jee-main 2003 Q21

jee-main · India Not Maths
A particle performing uniform circular motion has angular frequency is doubled \& its kinetic energy halved, then the new angular momentum is
(1) $\frac{\mathrm{L}}{4}$
(2) 2L
(3) 4L
(4) $\frac{\mathrm{L}}{2}$
A particle performing uniform circular motion has angular frequency is doubled \& its kinetic energy halved, then the new angular momentum is\\
(1) $\frac{\mathrm{L}}{4}$\\
(2) 2L\\
(3) 4L\\
(4) $\frac{\mathrm{L}}{2}$