The escape velocity for a body projected vertically upwards from the surface of earth is $11 \mathrm{~km/s}$. If the body is projected at an angle of $45^{\circ}$ with the vertical, the escape velocity will be\\
(1) $11\sqrt{2} \mathrm{~km/s}$\\
(2) $22 \mathrm{~km/s}$\\
(3) $11 \mathrm{~km/s}$\\
(4) $\frac{11}{\sqrt{2}} \mathrm{~km/s}$