jee-main 2003 Q54

jee-main · India Not Maths
A magnetic needle lying parallel to a magnetic field requires W units of work to turn it through $60^{\circ}$. The torque needed to maintain the needle in this position will be
(1) $\sqrt{3}\mathrm{~W}$
(2) W
(3) $\frac{\sqrt{3}}{2}\mathrm{~W}$
(4) 2W 
A magnetic needle lying parallel to a magnetic field requires W units of work to turn it through $60^{\circ}$. The torque needed to maintain the needle in this position will be\\
(1) $\sqrt{3}\mathrm{~W}$\\
(2) W\\
(3) $\frac{\sqrt{3}}{2}\mathrm{~W}$\\
(4) 2W
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