If the third term in the binomial expansion of $\left( 1 + x ^ { \log _ { 2 } x } \right) ^ { 5 }$ equals 2560, then a possible value of $x$ is (1) $4 \sqrt { 2 }$ (2) $\frac { 1 } { 8 }$ (3) $2 \sqrt { 2 }$ (4) $\frac { 1 } { 4 }$
If the third term in the binomial expansion of $\left( 1 + x ^ { \log _ { 2 } x } \right) ^ { 5 }$ equals 2560, then a possible value of $x$ is\\
(1) $4 \sqrt { 2 }$\\
(2) $\frac { 1 } { 8 }$\\
(3) $2 \sqrt { 2 }$\\
(4) $\frac { 1 } { 4 }$