jee-main 2019 Q85

jee-main · India · session1_10jan_shift1 Areas by integration
If the area enclosed between the curves $y = k x ^ { 2 }$ and $x = k y ^ { 2 } , ( k > 0 )$, is 1 sq. unit. Then $k$ is
(1) $\sqrt { 3 }$
(2) $\frac { 1 } { \sqrt { 3 } }$
(3) $\frac { \sqrt { 3 } } { 2 }$
(4) $\frac { 2 } { \sqrt { 3 } }$
If the area enclosed between the curves $y = k x ^ { 2 }$ and $x = k y ^ { 2 } , ( k > 0 )$, is 1 sq. unit. Then $k$ is\\
(1) $\sqrt { 3 }$\\
(2) $\frac { 1 } { \sqrt { 3 } }$\\
(3) $\frac { \sqrt { 3 } } { 2 }$\\
(4) $\frac { 2 } { \sqrt { 3 } }$