jee-main 2019 Q72

jee-main · India · session1_12jan_shift2 Chain Rule Limit Evaluation Involving Composition or Substitution

$\lim _ { x \rightarrow 1 ^ { - } } \frac { \sqrt { \pi } - \sqrt { 2 \sin ^ { - 1 } x } } { \sqrt { 1 - x } }$ is equal to
(1) $\sqrt { \pi }$
(2) $\sqrt { \frac { 2 } { \pi } }$
(3) $\frac { 1 } { \sqrt { 2 \pi } }$
(4) $\sqrt { \frac { \pi } { 2 } }$

$\lim _ { x \rightarrow 1 ^ { - } } \frac { \sqrt { \pi } - \sqrt { 2 \sin ^ { - 1 } x } } { \sqrt { 1 - x } }$ is equal to\\
(1) $\sqrt { \pi }$\\
(2) $\sqrt { \frac { 2 } { \pi } }$\\
(3) $\frac { 1 } { \sqrt { 2 \pi } }$\\
(4) $\sqrt { \frac { \pi } { 2 } }$

Paper Questions

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