jee-main 2021 Q66

jee-main · India · session1_25feb_shift1 Circles Circle Equation Derivation

The image of the point $( 3,5 )$ in the line $x - y + 1 = 0$, lies on :
(1) $( x - 2 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 4$
(2) $( x - 4 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 8$
(3) $( x - 4 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 16$
(4) $( x - 2 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 12$

The image of the point $( 3,5 )$ in the line $x - y + 1 = 0$, lies on :\\
(1) $( x - 2 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 4$\\
(2) $( x - 4 ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 8$\\
(3) $( x - 4 ) ^ { 2 } + ( y + 2 ) ^ { 2 } = 16$\\
(4) $( x - 2 ) ^ { 2 } + ( y - 2 ) ^ { 2 } = 12$

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