If the following system of linear equations\\
$2 x + y + z = 5$\\
$x - y + z = 3$\\
$x + y + a z = b$\\
has no solution, then :\\
(1) $a = - \frac { 1 } { 3 } , b \neq \frac { 7 } { 3 }$\\
(2) $a \neq \frac { 1 } { 3 } , b = \frac { 7 } { 3 }$\\
(3) $a \neq - \frac { 1 } { 3 } , b = \frac { 7 } { 3 }$\\
(4) $a = \frac { 1 } { 3 } , b \neq \frac { 7 } { 3 }$