jee-main 2021 Q78

jee-main · India · session4_31aug_shift1 Differential equations Solving Separable DEs with Initial Conditions

If $\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 2 ^ { x + y } - 2 ^ { x } } { 2 ^ { y } } , y ( 0 ) = 1$, then $y ( 1 )$ is equal to :
(1) $\log _ { 2 } \left( 1 + \mathrm { e } ^ { 2 } \right)$
(2) $\log _ { 2 } ( 2 \mathrm { e } )$
(3) $\log _ { 2 } ( 2 + e )$
(4) $\log _ { 2 } ( 1 + e )$

If $\frac { \mathrm { d } y } { \mathrm {~d} x } = \frac { 2 ^ { x + y } - 2 ^ { x } } { 2 ^ { y } } , y ( 0 ) = 1$, then $y ( 1 )$ is equal to :\\
(1) $\log _ { 2 } \left( 1 + \mathrm { e } ^ { 2 } \right)$\\
(2) $\log _ { 2 } ( 2 \mathrm { e } )$\\
(3) $\log _ { 2 } ( 2 + e )$\\
(4) $\log _ { 2 } ( 1 + e )$

Paper Questions

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