jee-main 2022 Q66

jee-main · India · session1_26jun_shift1 Standard trigonometric equations Inverse trigonometric equation

$\lim _ { x \rightarrow \frac { 1 } { \sqrt { 2 } } } \frac { \sin \left( \cos ^ { - 1 } x \right) - x } { 1 - \tan \left( \cos ^ { - 1 } x \right) }$ is equal to
(1) $\frac { 1 } { \sqrt { 2 } }$
(2) $\frac { - 1 } { \sqrt { 2 } }$
(3) $\sqrt { 2 }$
(4) $- 1$

$\lim _ { x \rightarrow \frac { 1 } { \sqrt { 2 } } } \frac { \sin \left( \cos ^ { - 1 } x \right) - x } { 1 - \tan \left( \cos ^ { - 1 } x \right) }$ is equal to\\
(1) $\frac { 1 } { \sqrt { 2 } }$\\
(2) $\frac { - 1 } { \sqrt { 2 } }$\\
(3) $\sqrt { 2 }$\\
(4) $- 1$

Paper Questions

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