Let $A = \{ n \in N :$ H.C.F.$( n , 45 ) = 1 \}$ and let $B = \{ 2k : k \in \{ 1 , 2 , \ldots , 100 \} \}$. Then the sum of all the elements of $A \cap B$ is $\_\_\_\_$.
Let $A = \{ n \in N :$ H.C.F.$( n , 45 ) = 1 \}$ and let $B = \{ 2k : k \in \{ 1 , 2 , \ldots , 100 \} \}$. Then the sum of all the elements of $A \cap B$ is $\_\_\_\_$.