Let a biased coin be tossed 5 times. If the probability of getting 4 heads is equal to the probability of getting 5 heads, then the probability of getting atmost two heads is\\
(1) $\frac { 46 } { 6 ^ { 4 } }$\\
(2) $\frac { 275 } { 6 ^ { 5 } }$\\
(3) $\frac { 41 } { 5 ^ { 5 } }$\\
(4) $\frac { 36 } { 5 ^ { 4 } }$