jee-main 2022 Q69

jee-main · India · session2_28jul_shift2 Composite & Inverse Functions Determine Domain or Range of a Composite Function

The function $f : R \rightarrow R$ defined by $f ( x ) = \lim _ { n \rightarrow \infty } \frac { \cos ( 2 \pi x ) - x ^ { 2 n } \sin ( x - 1 ) } { 1 + x ^ { 2 n + 1 } - x ^ { 2 n } }$ is continuous for all $x$ in
(1) $R - \{ - 1 \}$
(2) $R - \{ - 1,1 \}$
(3) $R - \{ 1 \}$
(4) $R - \{ 0 \}$

The function $f : R \rightarrow R$ defined by $f ( x ) = \lim _ { n \rightarrow \infty } \frac { \cos ( 2 \pi x ) - x ^ { 2 n } \sin ( x - 1 ) } { 1 + x ^ { 2 n + 1 } - x ^ { 2 n } }$ is continuous for all $x$ in\\
(1) $R - \{ - 1 \}$\\
(2) $R - \{ - 1,1 \}$\\
(3) $R - \{ 1 \}$\\
(4) $R - \{ 0 \}$

Paper Questions

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