In a triangle $A B C$, if $\cos A + 2 \cos B + \cos C = 2$ and the lengths of the sides opposite to the angles $A$ and $C$ are 3 and 7 respectively, then $\cos A - \cos C$ is equal to
(1) $\frac { 9 } { 7 }$
(2) $\frac { 10 } { 7 }$
(3) $\frac { 5 } { 7 }$
(4) $\frac { 3 } { 7 }$
In a triangle $A B C$, if $\cos A + 2 \cos B + \cos C = 2$ and the lengths of the sides opposite to the angles $A$ and $C$ are 3 and 7 respectively, then $\cos A - \cos C$ is equal to\\
(1) $\frac { 9 } { 7 }$\\
(2) $\frac { 10 } { 7 }$\\
(3) $\frac { 5 } { 7 }$\\
(4) $\frac { 3 } { 7 }$