jee-main 2023 Q80

jee-main · India · session2_12apr_shift1 Integration by Substitution Substitution to Compute an Indefinite Integral with Initial Condition

Let $I ( x ) = \int \sqrt { \frac { x + 7 } { x } } d x$ and $I ( 9 ) = 12 + 7 \log _ { e } 7$. If $I ( 1 ) = \alpha + 7 \log _ { e } ( 1 + 2 \sqrt { 2 } )$, then $\alpha ^ { 4 }$ is equal to $\_\_\_\_$ .

Let $I ( x ) = \int \sqrt { \frac { x + 7 } { x } } d x$ and $I ( 9 ) = 12 + 7 \log _ { e } 7$. If $I ( 1 ) = \alpha + 7 \log _ { e } ( 1 + 2 \sqrt { 2 } )$, then $\alpha ^ { 4 }$ is equal to $\_\_\_\_$ .

Paper Questions

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