jee-main 2024 Q66

jee-main · India · session1_27jan_shift1 Circles Circle Equation Derivation

Four distinct points $( 2 \mathrm { k } , 3 \mathrm { k } ) , ( 1,0 ) , ( 0,1 )$ and $( 0,0 )$ lie on a circle for $k$ equal to:
(1) $\frac { 2 } { 13 }$
(2) $\frac { 3 } { 13 }$
(3) $\frac { 5 } { 13 }$
(4) $\frac { 1 } { 13 }$

Four distinct points $( 2 \mathrm { k } , 3 \mathrm { k } ) , ( 1,0 ) , ( 0,1 )$ and $( 0,0 )$ lie on a circle for $k$ equal to:\\
(1) $\frac { 2 } { 13 }$\\
(2) $\frac { 3 } { 13 }$\\
(3) $\frac { 5 } { 13 }$\\
(4) $\frac { 1 } { 13 }$

Paper Questions

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